Punto de Fermat: 
minimiza la suma de sus distancias a los vértices

Inicio

PROCESO TERMINADO

A = (2, -1.98)
B = (10, -2)
C = (8.04, 1.56)
t1, c, a, b = Polygon(A, B, C)
F: (16, 4)
dif: abs(F - A) + abs(F - B) + abs(F - C)
t = 0.65 (slider from 0 to 1, step 0.01)
inc = 0.1 (slider from 0 to 0.1, step 0.01)
F0 = (7.730000000000029, -0.019000000000002466)
dif0 = 20
α = Angle(A, F, B)
β = Angle(C, F, A)
γ = Angle(B, F, C)
f = Segment(A, F)
g = Segment(B, F)
h = Segment(C, F)